协方差公式推导

cov(X,Y)=ni=1(XiX¯)(YiY¯)n=E[(XE[X])(YE[Y])]
<script type="math/tex; mode=display" id="MathJax-Element-1"> cov(X,Y)=\frac{\sum_{i=1}^{n}(X_i-\bar{X})(Y_i-\bar{Y})}{n}=E[(X-E[X])(Y-E[Y])] </script>
=E[XYE[X]YXE[Y]+E[X]E[Y]]
<script type="math/tex; mode=display" id="MathJax-Element-2"> =E[XY-E[X]Y-XE[Y]+E[X]E[Y]] </script>
因为均值计算是线性的,即(a和b均为常数):
E[aX+bY]=aE[X]+bE[Y]
<script type="math/tex; mode=display" id="MathJax-Element-3"> E[aX+bY]=aE[X]+bE[Y] </script>
则我们有:
E[XYE[X]YXE[Y]+E[X]E[Y]]
<script type="math/tex; mode=display" id="MathJax-Element-4"> E[XY-E[X]Y-XE[Y]+E[X]E[Y]] </script>
=E[XY]E[X]E[Y]E[X]E[Y]+E[X]E[Y]
<script type="math/tex; mode=display" id="MathJax-Element-5"> =E[XY]-E[X]E[Y]-E[X]E[Y]+E[X]E[Y] </script>
=E[XY]E[X]E[Y]
<script type="math/tex; mode=display" id="MathJax-Element-6"> =E[XY]-E[X]E[Y] </script>
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